Question

Here's the way I did it.'

def biggest(a,b,c):
        z=a
        if b>z: z=b
        if c>z: z=c
        return z

    print biggest(5,23,8)

``Here's the way I did it.

print z

Answer 1

3	As I was thinking about it I came up with this one: `def bigger(a,b): if a > b: return a return b def biggest(a, b, c): return bigger(a, bigger(b, c))` link answered 04 Mar '12, 22:20 pmoriarty 5.5k●5●23●77 1 Me like! :-) (04 Mar '12, 22:25) Rafael Esper...

Answer 2

2	Another solution, though perhaps using stuff not yet covered: `def biggest(a,b,c): L = [a,b,c] L.sort() return L[2]` link answered 04 Mar '12, 22:14 Rafael Esper... 12.8k●66●128●192 edited 04 Mar '12, 22:23

Answer 3

1	Here's how I did it: `def biggest(a, b, c): if a > b: if a > c: return a else: if b > c: return b else: return c return c` link answered 04 Mar '12, 22:05 pmoriarty 5.5k●5●23●77

Answer 4

1	Just to add to the mix... `def biggest(a, b, c): if (a < b) or (a < c): if (b < c): return c else: return b else: return a` link answered 04 Mar '12, 22:28 dedos 1.4k●13●22●30

Answer 5

1	What dedos said. :) `a = 45 b = 355 c = 2 def biggest(a, b, c): if a > b and a > c: return a if b > a and b > c: return b if c > a and c > b: return c` link answered 04 Mar '12, 22:28 James Viebke 1.5k●2●18●31

Answer 6

0	Same as Mainframe, except reusing a: `def biggest(a,b,c): if a < b: a = b if a < c: a = c return a print biggest(1,2,3) print biggest(2,3,1) print biggest(3,1,2)` link answered 07 Mar '12, 11:42 tcabeen 11●1

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